Formula-overview

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A(n)

B(n)

C(n)

(n)

E(n)

T(n)

S(n)

       

2

0

2

(s)

0

0

1

0

2

2

6

(p)

1

2

[He]

4

2

8

8

10

(d)

2

10

[Ne]

12

10

8

18

14

(f)

3

18

[Ar]

21

28

18

32

18

(g)

4

36

[Kr]

39

60

18

50

22

(h)

5

54

[Xe]

58

110

32

72

26

(i)

6

86

[Rn]

90

182

32

98

30

(j)

7

118

[Uuo]

123

280

50

128

34

(k)

8

168

[Uho]

173

408

50

162

38

(l)

9

218

[Buo]

224

570

72

200

42

10

290

296

770

72

242

46

11

362

369

1012

98

288

50

12

460

467

1300

98

338

54

13

558

566

1638

128

392

58

14

686

694

2030

128

450

62

15

814

823

2480

162

512

66

16

976

985

2992

162

578

70

17

1138

1148

3570

200

648

74

18

1338

1348

4218

200

722

78

19

1538

1549

4940

242

800

82

20

1780

1791

5740

242

882

86

21

2022

2034

6622

288

968

90

22

2310

2322

7590

 

Pauli

  

Noble-gas

Truss

Singularity

A(n)

B(n)

C(n)

(n)

E(n)

T(n)

S(n)

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Top   formel.zip   [Excel-File with new formulas  (53KB)]   Excel-file "formel.zip" 
   

  Basic
  
  Numbers are equal for all n> -3 
  A(n)= ((2n+3+(-1)^n)^2)/8  
  
  A(n)= Int((n+2)/2) ^ 2 * 2
   A(n)= E(n) - E(n-1)
   
  
  B(n) = n ^ 2 * 2    (Pauli)
  B(n) = B(n-1)+ C(n-1)
   
  
  C(n)=  4 * n+ 2
  
  C(n)= ( n +1 ) * 4 - 2
  
  C(n)= 2 * ( 2*n+1 )
   
  
  E(n) = E(n-1) + A(n)
  
  

  
  
 
T(n)=E(n)+(int(n+1)/2)+1
  FNT = Int((n + 1) / 2) + 1
 
  
  S(n)= S(n-1 ) + B(n)
  
  
  S(n)= n* ( n +1 )*( 2* n+1)/3
      
  Excel  and References   Excel file: formula.xls (238 KB)
  
     
  Martin Gardner      Antimatter and chemistry   
  
  A(n)=QUADRATESUMME(ABRUNDEN((A(n)+2)/2;0))*2
  A(n)=SUMSQ(ROUNDDOWN((A(n)+2)/2,0))*2  
    
  
  B(n)=QUADRATESUMME(B(n))*2     B(n)=SUMSQ(B(n))*2
  B(n)= S(n) - S(n-1)
   
  
  C(n)= B( n +1 ) - B(n)
   
   William A. Stein
  
 
Outblocking of Elements
    
  
  E(n)=QUADRATESUMME(ABRUNDEN((E(n)+2)/2;0))*2+E(n-1) 
  E(n)=SUMSQ(ROUNDDOWN((E(n)+2)/2,0))*2+E(n-1)

  Inert-gas algorithm (rare-gas)  
  
  
   T(n)=E(n)+(ABRUNDEN((n+1)/2;0))+1
   T(n)=E(n)+(ROUNDDOWN((n+1)/2,0))+1
 
  
  S(n)=QUADRATESUMME(S(n))*2+S(n-1)
  S(n)=SUMSQ(S(n))*2+S(n-1)
  
  Prof. Germain Kreweras    Singularity algorithm  
   

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research

ID Number: A006331 (Formerly M1963)

S(n) = Sequence: 0,2,10,28,60,110,182,280,408,570,770,1012,1300,1638,2030,
2 480,2992,3570,4218,4940,5740,6622,7590 , 8648, 9800, 11050,
12402, 13860, 15428, 17110, 18910, 20832, 22880, 25058, 27370, 29820,
32412, 35150, 38038, 41080, 44280 ... (Numbers checked for correctness)

Name: n*(n+1)*(2n+1)/3.

Comments: Triangles in rhombic matchstick arrangement of side n.
Maximum accumulated number of electrons at energy level n - 
Feb 28 2000

Mr. Scott A. Brown      http://home.neo.rr.com/scottbrown/chall.html 
webpage:  http://home.neo.rr.com/scottbrown
e-mail:  scottbrown
@neo.rr.com

References Cahiers du Bureau Universitaire de Recherche Opérationnelle,
Institut de Statistique, Université de Paris, 6 (1965), circa p.82, 
but I think volume, page or year must be wrong. Author is probably
Germain Kreweras.

Links: Basic atomic information

Formula: G.f.: x*(2+2*x)/(1-x)^4. a(n)=2*C(n+1,3)+2*C(n+2,3).
Program: (PARI) a(n)=n*(n+1)*(2*n+1)/3
 
Lit: Germain Kreweras

[1] "Les décisions collectives"; Mathématiques et Sciences Humaines; 
No. 2; Spring, 1963; 25-35; #1500. 

[2] "Représentation polyédrique des préordres complets finis et application 
à l'agrégation des préférences"; La Décision; Colloque du CNRS; 
Aix-en-Provence; 1969; 137-151; #1830. 

[3]"Sur Quelques Problèmes Relatifs au Vote Pondéré"; Mathématiques et 
Sciences Humaines; No. 84; Winter, 1983; 45-63; #258.

[Picture]

This produces A001105 doubled up. 

References Martin Gardner, The Colossal Book of Mathematics, Classic Puzzles,
Paradoxes, and Problems, Chapter 2 entitled "The Calculus of Finite
Differences," W. W. Norton & Company, New York, 2001, pages 12-13.

Links: Index entries for sequences related to Chebyshev polynomials.
See also: a(n)= ((-1)^(n+1))*A053120(2*n,2).
Keywords: nonn
Offset: 0
Author: Bernd.Walter
@frankfurt.netsurf.de

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Top   ID Number: A016825

C(n) = Sequence: 2,6,10,14,18,22,26,30,34,38,42,46,50,54,58,62,66,70,74,78,
82,86,90,94,98,102,106,110,114,118,122,126,130,134,138,142,146,150,154,
158,162,166,170,174,178,182,186,190    (Numbers checked for correctness)

Name: 4n+2

Comments: Continued fraction for (e-1)/(e+1).
No solutions to a(n)=b^2-c^2 - Henry Bottomley
(se16
@btinternet.com), Jan 13 2001
Apart from initial term(s), di
mension of the space of weight 2n
cuspidal newforms for Gamma_0( 70 ).
References J. R. Goldman, The Queen of Mathematics, 1998, p. 70.

Links: William A. Stein  was
@math.berkeley.edu ,
Dimensions of the spaces S_k^{new}(Gamma_0(N))
William A. Stein (was@math.berkeley.edu), The modular forms database
E. W. Weisstein, Link to a section of The World of Mathematics. (Currently unavailable)
Index entries for continued fractions for constants
Keywords: nonn,easy,nice
Offset: 0
Author: njas

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Top   ID Number: A000952 (Formerly M1574 and N0615)

Sequence: 2,6,10,14,18,26,30,38,42,46,50
Name: Orders n == 2 (mod 4) of conference matrices.
Comments: A conference matrix of order n is an n X n {-1,0,+1} matrix A such that A A' =
(n-1)I.
If n == 2 (mod 4) then a necessary condition is that n-1 is a sum of 2
squares. It is conjectured that this condition is also sufficient.
References V. Belevitch, Conference matrices and Hadamard matrices, Ann. Soc.
Scientifique Bruxelles, 82 (I) (1968), 13-32.
CRC Handbook of Combinatorial Designs, 1996, Chapter 52.
F. J. MacWilliams and N. J. A. Sloane, The Theory of Error-Correcting
Codes, Elsevier-North Holland, 1978, p. 56.
Example: The essentially unique conference matrix of order 6:
0 +1 +1 +1 +1 +1
+1 0 +1 -1 -1 +1
+1 +1 0 +1 -1 -1
+1 -1 +1 0 +1 -1
+1 -1 -1 +1 0 +1
+1 +1 -1 -1 +1 0
Keywords: nonn,hard,nice
Offset: 1
Author(s): njas
Extension: 54 seems to be the smallest order for which it is not known whether a matrix
exists.
Show internal format for above sequence? 

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[Picture]    Arbeitsnotiz 

[Picture]    My Notes

Ich habe mich sehr über die Formel
S(n)=n*(n+1)*(2*n+1)/3  gefreut.
Für den Atomkern/Protonen ist sie möglicherweise eine der wichtigsten Grenzfunktion für die Quarks, nicht nur die Tripplets werden als mögliche Unterfunktionen eines Produkts dargestellt, sondern die Werte sind eindeutig gleich mit der Singularität der Atomhülle. Die Formel wertet die Singularitäts- Theorie sehr stark auf.  Dadurch ist  ein starker Bezug zwischen Atomhülle und Atomkern (Quarks) zu erkennen.
I am quite pleased over the formula
S(n)=n*(n+1)*(2*n+1)/3.
It is possibly one of the most important limiting functions there are for the atomic nucleus/protons:  not only are the triplets shown as possible subfunctions of a product, but the values are unambigously identical with the singularity of the atomic shell.  The formula makes singularity theory much more important, revealing a strong connection between atomic shell and nucleus (quarks).
Neuester Theorie zu Folge lagern sich die Protonen im Atomkernzentrum an und die Neutronen bilden eine isolierende Schicht(en) darum. >>zu Einfach, da nur Ladungspezifisch betrachtet und die Art wie das Messergebnis erzeugt wurde, nicht mitberücksichtigt ist.  Es stellt jedoch einer der möglichen Extremfälle von kompletter Ladungsverschiebung innerhalb des Atomkernes dar.<<According to the most recent theory, protons are concentrated in the core of a nucleus and neutrons form an isolating layer(s) around them.  My view:  "Too simple, since this takes into consideration charge only, and the way in which the results of measurement were produced is not taken into account.  It does, of course, represent one of the possible extreme cases of complete charge shift inside the atomic nucleus."
Für mich bleibt die Theorie der Protonen Neutronen Durchmischung weiterhin bestehen, da nur durch das Ladungswechseln [ Ladung des Protons(a) wird in ein beliebiges Neutron(b) verschoben, Proton(a) wird zum  Neutron(a) und  Neutron(b) wird Proton(b), usw..] Dadurch bleibt die jeweilige Ladung als Teilladung im Atomkern frei beweglich bzw. synchron zu der Elektronenladung in der Atomhülle.In my view the theory of proton-neutron intermixture is still valid, since it is only thus that charge exchange can occur [the charge of proton(a) is transferred to any given neutron(b), and proton(a) becomes neutron(a) while neutron(b) becomes proton(b), etc.].  The respective charge thereby remains freely mobile as a partial charge in the nucleus or, as the case may be, synchronized with the electron charge in the atomic shell.
[ev. bedingt gerade dieses Verschieben der Protonenladung im Atomkern die Struktur der Atomhülle, über Zusammenhänge unbedingt nachdenken]. Die statische Masse des Atomkerns als Grundgerüst steht einer dynamischen Ladung der Protonen gegenüber?[Possibly it is precisely this transfer of proton charge in the nucleus which determines the structure of the shell.  We definitely have to think about connections of this sort.]  Does the static mass of the nucleus, as a structural base, serve as a counterpoise to the dynamic charge of the protons?

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APSIDIUM ©Created:

  2001-01-04

This page as PDF-file
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2003-04-26

Thanks for translation to Brian T. Regan

Thanks to Scott A. Brown and BOB