![[Picture]](../images/aglarule.gif){kind=small}
Multi-elektrons-model at the example of Unbiunium [Ubu] No.121
| Sc 21 | Y 39 | La 57 | Ac 89 | Ubu 121 | Usu 171 | Bbu 221 |
How many shells does the atom No. 121 have?
| The answer is, if electrons reaches the formula-value. | E( n) = E ( n-1) + A( n) | |
| No. 121 | ||||
| Shell 1 | K | E( 1)= 2 | Yes | > |
| Shell 2 | L | E( 2)= 10 | Yes | > |
| Shell 3 | M | E( 4)= 18 | Yes | > |
| Shell 4 | N | E( 4)= 36 | Yes | > |
| Shell 5 | O | E( 5)= 54 | Yes | > |
| Shell 6 | P | E( 6)= 86 | Yes | > |
| Shell 7 | Q | E( 7)= 118 | Yes | > |
| Shell 8 | R | E( 8 )= 168 | No | < |
That means for the atom [Ubu]. It is settled between noble-gas 118 and 168. [118<121<168]
Unbiunium has eight shells. (All shells = 8)
 How do I get the number of the inner and outer shells? | ||||
With this formula you can calculate both areas. | ![[Picture]](ubu.gif) | |||
| IS = int (AS /2 +0.5) OS=AS - IS | IS = inner shells | |||
| OS= outer shells | ||||
| AS= all shells | ||||
| IS = int (AS /2 +0.5) | AS= 8 | OS=AS - IS | ||
| IS = int(8/2 +0.5) | IS = 4 | OS= 8-4 OS=4 | ||
| That means here | 4 inner shells | and 4 outer shells |
How do the inner orbitales / shells be filled?
| The answer is, if electrons reaches the formula-value. | B( n)= n ^ 2 * 2 | shells | |
and | C( n)= ( n+1 ) * 4 - 2 | orbitals |
s | p | d | f | g | 121 | |||
Shell 1 | B( 1)= 2 | C( 0 )= | 2 | 119 | ||||
Shell 2 | B( 2)= 8 | C( 0 to 1 )= | 2 | 6 | 111 | |||
Shell 3 | B( 3)= 18 | C( 0 to 2 )= | 2 | 6 | 10 | 93 | ||
Shell 4 | B( 4)= 32 | C( 0 to 3 )= | 2 | 6 | 10 | 14 | 61 | |
Reminds at the Singularity Algorithm S(4)=60 again, alle shells are filled and fully occupied.
Therefore, all shells become condensed to a (single) ball.
see: Compression of inner-orbitals/shells
| How do the outer orbitales / shells be filled? | ![[Picture]](ubu121f.gif) | |||
| The answer is with Classic rule-distribution | ||||
| yellow = inner electrons | S(4)=60 | |||
| red = outer electrons | 121-60=61 | |||
| blue = free orbitales (up to Inert-gas No.168) | 168-121=47 | |||
| s | p | d | f | g | 61 | |||
| Shell 5 | B( 5)=50 | C( 0 to 3)= | 2 | 6 | 10 | 14 | 1 | 28 |
| Shell 6 | B( 6)=72 | C( 0 to 2)= | 2 | 6 | 10 | 10 | ||
| Shell 7 | B( 7)=98 | C( 0 to 1)= | 2 | 6 | 2 | |||
| Shell 8 | B( 8)=128 | C( 0)= | 2 | 0 | ||||
The last electron (Valence Electron) occupies the 5g1-orgital.
![[Picture]](ubu121.gif)
You can find the classic solution-scheme for element 121 under
http:// www.utdallas.edu/~parr/chm1311/1311ss3.html Solutions for CHM 1311 / 8.
(However, you should think over " 6h 1 at 169!" again, because 221 will be the right one ?)
| APSIDIUM ©
| Created: Last Updated: | 2001-01-10 2003 -07-09 |  ubu_121.pdf |
